일 | 월 | 화 | 수 | 목 | 금 | 토 |
---|---|---|---|---|---|---|
1 | 2 | 3 | 4 | |||
5 | 6 | 7 | 8 | 9 | 10 | 11 |
12 | 13 | 14 | 15 | 16 | 17 | 18 |
19 | 20 | 21 | 22 | 23 | 24 | 25 |
26 | 27 | 28 | 29 | 30 | 31 |
- vuejs #vue #js #프론트엔드 #nodejs #클라이언트사이드 #템플릿엔진
- Arrays
- 스프링
- HashMap
- @Scheduled
- pom.xml
- spring scheduler
- springboot
- 프로젝트 구조
- Spring Mail
- Spring
- maven
- 의존성관리
- 스프링 부트
- Spring Boot
- 스프링 메일
- mybatis
- GOF
- list
- java
- codility
- thymeleaf
- Dependency
- 코딩테스트
- 스프링부트
- C++
- 프로그래머스
- Collections
- 스프링 스케줄러
- pair
- Today
- Total
Rooted In Develop
[Codility] Leader - Dominator / Java 본문
1. 문제
An array A consisting of N integers is given. The dominator of array A is the value that occurs in more than half of the elements of A.
For example, consider array A such that
A[0] = 3 A[1] = 4 A[2] = 3 A[3] = 2 A[4] = 3 A[5] = -1 A[6] = 3 A[7] = 3
The dominator of A is 3 because it occurs in 5 out of 8 elements of A (namely in those with indices 0, 2, 4, 6 and 7) and 5 is more than a half of 8.
Write a function
class Solution { public int solution(int[] A); }
that, given an array A consisting of N integers, returns index of any element of array A in which the dominator of A occurs. The function should return −1 if array A does not have a dominator.
For example, given array A such that
A[0] = 3 A[1] = 4 A[2] = 3 A[3] = 2 A[4] = 3 A[5] = -1 A[6] = 3 A[7] = 3
the function may return 0, 2, 4, 6 or 7, as explained above.
Write an efficient algorithm for the following assumptions:
- N is an integer within the range [0..100,000];
- each element of array A is an integer within the range [−2,147,483,648..2,147,483,647].
Copyright 2009–2020 by Codility Limited. All Rights Reserved. Unauthorized copying, publication or disclosure prohibited.
2. 코드
import java.util.*;
class Solution {
public int solution(int[] A) {
HashMap<Integer, Integer> map = new HashMap<>();
for(int i=0; i<A.length; i++) {
map.put(A[i], map.getOrDefault(A[i], 0) + 1);
}
int max = 0;
int maxKey = 0;
for(Integer key : map.keySet()) {
int count = map.get(key);
if(count > max) {
max = count;
maxKey = key;
}
}
if(max <= A.length / 2)
return -1;
for(int i=0; i<A.length; i++) {
if(A[i] == maxKey)
return i;
}
return -1;
}
}
'Algorithm Test > Java' 카테고리의 다른 글
[Codility] Leader - EquiLeader / Java (0) | 2020.06.16 |
---|---|
[Codility] Stacks and Queues - Nesting / Java (0) | 2020.06.15 |
[Codility] Stacks and Queues - Fish / Java (0) | 2020.06.15 |
[Codility] Stacks and Queues - Brackets / Java (0) | 2020.06.15 |
[Codility] Sorting - Triangle / Java (0) | 2020.06.14 |